
Initial complexity problem:
1:	T:
		(Comp: ?, Cost: 1)    f2(Ar_0, Ar_1, Ar_2) -> Com_1(f2(Ar_0 + 1, Ar_1 + 1, Ar_2)) [ 1 >= Ar_0 ]
		(Comp: ?, Cost: 1)    f2(Ar_0, Ar_1, Ar_2) -> Com_1(f2(Ar_0 + 1, Ar_1 + 1, Ar_2)) [ 2 >= Ar_1 /\ Ar_0 >= 2 ]
		(Comp: ?, Cost: 1)    f2(Ar_0, Ar_1, Ar_2) -> Com_1(f300(Ar_0, Ar_1, Fresh_0)) [ Ar_1 >= 3 /\ Ar_0 >= 2 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2) -> Com_1(f2(Ar_0, Ar_1, Ar_2))
		(Comp: 1, Cost: 0)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f1(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

Repeatedly propagating knowledge in problem 1 produces the following problem:
2:	T:
		(Comp: ?, Cost: 1)    f2(Ar_0, Ar_1, Ar_2) -> Com_1(f2(Ar_0 + 1, Ar_1 + 1, Ar_2)) [ 1 >= Ar_0 ]
		(Comp: ?, Cost: 1)    f2(Ar_0, Ar_1, Ar_2) -> Com_1(f2(Ar_0 + 1, Ar_1 + 1, Ar_2)) [ 2 >= Ar_1 /\ Ar_0 >= 2 ]
		(Comp: ?, Cost: 1)    f2(Ar_0, Ar_1, Ar_2) -> Com_1(f300(Ar_0, Ar_1, Fresh_0)) [ Ar_1 >= 3 /\ Ar_0 >= 2 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2) -> Com_1(f2(Ar_0, Ar_1, Ar_2))
		(Comp: 1, Cost: 0)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f1(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

A polynomial rank function with
	Pol(f2) = 1
	Pol(f300) = 0
	Pol(f1) = 1
	Pol(koat_start) = 1
orients all transitions weakly and the transition
	f2(Ar_0, Ar_1, Ar_2) -> Com_1(f300(Ar_0, Ar_1, Fresh_0)) [ Ar_1 >= 3 /\ Ar_0 >= 2 ]
strictly and produces the following problem:
3:	T:
		(Comp: ?, Cost: 1)    f2(Ar_0, Ar_1, Ar_2) -> Com_1(f2(Ar_0 + 1, Ar_1 + 1, Ar_2)) [ 1 >= Ar_0 ]
		(Comp: ?, Cost: 1)    f2(Ar_0, Ar_1, Ar_2) -> Com_1(f2(Ar_0 + 1, Ar_1 + 1, Ar_2)) [ 2 >= Ar_1 /\ Ar_0 >= 2 ]
		(Comp: 1, Cost: 1)    f2(Ar_0, Ar_1, Ar_2) -> Com_1(f300(Ar_0, Ar_1, Fresh_0)) [ Ar_1 >= 3 /\ Ar_0 >= 2 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2) -> Com_1(f2(Ar_0, Ar_1, Ar_2))
		(Comp: 1, Cost: 0)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f1(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

A polynomial rank function with
	Pol(f2) = -V_1 + 3
	Pol(f300) = -V_1
	Pol(f1) = -V_1 + 3
	Pol(koat_start) = -V_1 + 3
orients all transitions weakly and the transition
	f2(Ar_0, Ar_1, Ar_2) -> Com_1(f2(Ar_0 + 1, Ar_1 + 1, Ar_2)) [ 1 >= Ar_0 ]
strictly and produces the following problem:
4:	T:
		(Comp: Ar_0 + 3, Cost: 1)    f2(Ar_0, Ar_1, Ar_2) -> Com_1(f2(Ar_0 + 1, Ar_1 + 1, Ar_2)) [ 1 >= Ar_0 ]
		(Comp: ?, Cost: 1)           f2(Ar_0, Ar_1, Ar_2) -> Com_1(f2(Ar_0 + 1, Ar_1 + 1, Ar_2)) [ 2 >= Ar_1 /\ Ar_0 >= 2 ]
		(Comp: 1, Cost: 1)           f2(Ar_0, Ar_1, Ar_2) -> Com_1(f300(Ar_0, Ar_1, Fresh_0)) [ Ar_1 >= 3 /\ Ar_0 >= 2 ]
		(Comp: 1, Cost: 1)           f1(Ar_0, Ar_1, Ar_2) -> Com_1(f2(Ar_0, Ar_1, Ar_2))
		(Comp: 1, Cost: 0)           koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f1(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

A polynomial rank function with
	Pol(f2) = -V_2 + 3
	Pol(f300) = -V_2
	Pol(f1) = -V_2 + 3
	Pol(koat_start) = -V_2 + 3
orients all transitions weakly and the transition
	f2(Ar_0, Ar_1, Ar_2) -> Com_1(f2(Ar_0 + 1, Ar_1 + 1, Ar_2)) [ 2 >= Ar_1 /\ Ar_0 >= 2 ]
strictly and produces the following problem:
5:	T:
		(Comp: Ar_0 + 3, Cost: 1)    f2(Ar_0, Ar_1, Ar_2) -> Com_1(f2(Ar_0 + 1, Ar_1 + 1, Ar_2)) [ 1 >= Ar_0 ]
		(Comp: Ar_1 + 3, Cost: 1)    f2(Ar_0, Ar_1, Ar_2) -> Com_1(f2(Ar_0 + 1, Ar_1 + 1, Ar_2)) [ 2 >= Ar_1 /\ Ar_0 >= 2 ]
		(Comp: 1, Cost: 1)           f2(Ar_0, Ar_1, Ar_2) -> Com_1(f300(Ar_0, Ar_1, Fresh_0)) [ Ar_1 >= 3 /\ Ar_0 >= 2 ]
		(Comp: 1, Cost: 1)           f1(Ar_0, Ar_1, Ar_2) -> Com_1(f2(Ar_0, Ar_1, Ar_2))
		(Comp: 1, Cost: 0)           koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f1(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

Complexity upper bound Ar_0 + Ar_1 + 8

Time: 0.040 sec (SMT: 0.034 sec)
