
Initial complexity problem:
1:	T:
		(Comp: ?, Cost: 1)    f0(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4))
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: 1, Cost: 0)    koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f0(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

Repeatedly propagating knowledge in problem 1 produces the following problem:
2:	T:
		(Comp: 1, Cost: 1)    f0(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4))
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: 1, Cost: 0)    koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f0(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

A polynomial rank function with
	Pol(f0) = 1
	Pol(f1) = 1
	Pol(f2) = 0
	Pol(koat_start) = 1
orients all transitions weakly and the transition
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
strictly and produces the following problem:
3:	T:
		(Comp: 1, Cost: 1)    f0(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4))
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: 1, Cost: 0)    koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f0(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

A polynomial rank function with
	Pol(f0) = 1
	Pol(f1) = -V_3 + 1
	Pol(f2) = -V_3
	Pol(koat_start) = 1
orients all transitions weakly and the transitions
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
strictly and produces the following problem:
4:	T:
		(Comp: 1, Cost: 1)    f0(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4))
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: 1, Cost: 0)    koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f0(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

Applied AI with 'oct' on problem 4 to obtain the following invariants:
  For symbol f1: X_3 >= 0


This yielded the following problem:
5:	T:
		(Comp: 1, Cost: 0)    koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f0(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ 0 <= 0 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: 1, Cost: 1)    f0(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4))
	start location:	koat_start
	leaf cost:	0

By chaining the transition koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f0(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ 0 <= 0 ] with all transitions in problem 5, the following new transition is obtained:
	koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4)) [ 0 <= 0 ]
We thus obtain the following problem:
6:	T:
		(Comp: 1, Cost: 1)    koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4)) [ 0 <= 0 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: 1, Cost: 1)    f0(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4))
	start location:	koat_start
	leaf cost:	0

Testing for reachability in the complexity graph removes the following transition from problem 6:
	f0(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4))
We thus obtain the following problem:
7:	T:
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)    koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ] with all transitions in problem 7, the following new transitions are obtained:
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 20, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ Ar_0 - 10 >= 101 ]
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 1, Ar_1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 ]
We thus obtain the following problem:
8:	T:
		(Comp: 1, Cost: 2)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 20, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ Ar_0 - 10 >= 101 ]
		(Comp: 1, Cost: 2)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 1, Ar_1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)    koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 1, Ar_1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 ] with all transitions in problem 8, the following new transition is obtained:
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 9, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 ]
We thus obtain the following problem:
9:	T:
		(Comp: 1, Cost: 3)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 9, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 ]
		(Comp: 1, Cost: 2)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 20, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ Ar_0 - 10 >= 101 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)    koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 9, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 ] with all transitions in problem 9, the following new transitions are obtained:
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 19, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 ]
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 2, Ar_1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ 100 >= Ar_0 - 9 ]
We thus obtain the following problem:
10:	T:
		(Comp: 1, Cost: 4)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 19, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 ]
		(Comp: 1, Cost: 4)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 2, Ar_1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ 100 >= Ar_0 - 9 ]
		(Comp: 1, Cost: 2)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 20, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ Ar_0 - 10 >= 101 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)    koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 19, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 ] with all transitions in problem 10, the following new transition is obtained:
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 8, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 ]
We thus obtain the following problem:
11:	T:
		(Comp: 1, Cost: 5)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 8, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 ]
		(Comp: 1, Cost: 4)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 2, Ar_1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ 100 >= Ar_0 - 9 ]
		(Comp: 1, Cost: 2)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 20, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ Ar_0 - 10 >= 101 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)    koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 8, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 ] with all transitions in problem 11, the following new transition is obtained:
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 18, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 ]
We thus obtain the following problem:
12:	T:
		(Comp: 1, Cost: 6)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 18, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 ]
		(Comp: 1, Cost: 4)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 2, Ar_1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ 100 >= Ar_0 - 9 ]
		(Comp: 1, Cost: 2)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 20, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ Ar_0 - 10 >= 101 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)    koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 18, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 ] with all transitions in problem 12, the following new transition is obtained:
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 7, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 ]
We thus obtain the following problem:
13:	T:
		(Comp: 1, Cost: 7)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 7, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 ]
		(Comp: 1, Cost: 4)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 2, Ar_1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ 100 >= Ar_0 - 9 ]
		(Comp: 1, Cost: 2)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 20, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ Ar_0 - 10 >= 101 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)    koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 7, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 ] with all transitions in problem 13, the following new transition is obtained:
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 17, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 ]
We thus obtain the following problem:
14:	T:
		(Comp: 1, Cost: 8)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 17, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 ]
		(Comp: 1, Cost: 4)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 2, Ar_1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ 100 >= Ar_0 - 9 ]
		(Comp: 1, Cost: 2)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 20, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ Ar_0 - 10 >= 101 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)    koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 17, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 ] with all transitions in problem 14, the following new transition is obtained:
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 6, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 ]
We thus obtain the following problem:
15:	T:
		(Comp: 1, Cost: 9)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 6, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 ]
		(Comp: 1, Cost: 4)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 2, Ar_1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ 100 >= Ar_0 - 9 ]
		(Comp: 1, Cost: 2)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 20, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ Ar_0 - 10 >= 101 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)    koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 6, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 ] with all transitions in problem 15, the following new transition is obtained:
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 16, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 /\ Ar_0 - 6 >= 101 ]
We thus obtain the following problem:
16:	T:
		(Comp: 1, Cost: 10)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 16, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 /\ Ar_0 - 6 >= 101 ]
		(Comp: 1, Cost: 4)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 2, Ar_1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ 100 >= Ar_0 - 9 ]
		(Comp: 1, Cost: 2)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 20, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ Ar_0 - 10 >= 101 ]
		(Comp: 1, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: ?, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: 1, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)     koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 16, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 /\ Ar_0 - 6 >= 101 ] with all transitions in problem 16, the following new transition is obtained:
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 5, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 /\ Ar_0 - 6 >= 101 /\ 100 >= Ar_0 - 16 ]
We thus obtain the following problem:
17:	T:
		(Comp: 1, Cost: 11)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 5, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 /\ Ar_0 - 6 >= 101 /\ 100 >= Ar_0 - 16 ]
		(Comp: 1, Cost: 4)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 2, Ar_1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ 100 >= Ar_0 - 9 ]
		(Comp: 1, Cost: 2)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 20, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ Ar_0 - 10 >= 101 ]
		(Comp: 1, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: ?, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: 1, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)     koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 5, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 /\ Ar_0 - 6 >= 101 /\ 100 >= Ar_0 - 16 ] with all transitions in problem 17, the following new transition is obtained:
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 15, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 /\ Ar_0 - 6 >= 101 /\ 100 >= Ar_0 - 16 /\ Ar_0 - 5 >= 101 ]
We thus obtain the following problem:
18:	T:
		(Comp: 1, Cost: 12)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 15, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 /\ Ar_0 - 6 >= 101 /\ 100 >= Ar_0 - 16 /\ Ar_0 - 5 >= 101 ]
		(Comp: 1, Cost: 4)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 2, Ar_1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ 100 >= Ar_0 - 9 ]
		(Comp: 1, Cost: 2)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 20, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ Ar_0 - 10 >= 101 ]
		(Comp: 1, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: ?, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: 1, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)     koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 15, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 /\ Ar_0 - 6 >= 101 /\ 100 >= Ar_0 - 16 /\ Ar_0 - 5 >= 101 ] with all transitions in problem 18, the following new transition is obtained:
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 4, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 /\ Ar_0 - 6 >= 101 /\ 100 >= Ar_0 - 16 /\ Ar_0 - 5 >= 101 /\ 100 >= Ar_0 - 15 ]
We thus obtain the following problem:
19:	T:
		(Comp: 1, Cost: 13)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 4, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 /\ Ar_0 - 6 >= 101 /\ 100 >= Ar_0 - 16 /\ Ar_0 - 5 >= 101 /\ 100 >= Ar_0 - 15 ]
		(Comp: 1, Cost: 4)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 2, Ar_1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ 100 >= Ar_0 - 9 ]
		(Comp: 1, Cost: 2)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 20, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ Ar_0 - 10 >= 101 ]
		(Comp: 1, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: ?, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: 1, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)     koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 4, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 /\ Ar_0 - 6 >= 101 /\ 100 >= Ar_0 - 16 /\ Ar_0 - 5 >= 101 /\ 100 >= Ar_0 - 15 ] with all transitions in problem 19, the following new transition is obtained:
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 14, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 /\ Ar_0 - 6 >= 101 /\ 100 >= Ar_0 - 16 /\ Ar_0 - 5 >= 101 /\ 100 >= Ar_0 - 15 /\ Ar_0 - 4 >= 101 ]
We thus obtain the following problem:
20:	T:
		(Comp: 1, Cost: 14)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 14, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 /\ Ar_0 - 6 >= 101 /\ 100 >= Ar_0 - 16 /\ Ar_0 - 5 >= 101 /\ 100 >= Ar_0 - 15 /\ Ar_0 - 4 >= 101 ]
		(Comp: 1, Cost: 4)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 2, Ar_1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ 100 >= Ar_0 - 9 ]
		(Comp: 1, Cost: 2)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 20, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ Ar_0 - 10 >= 101 ]
		(Comp: 1, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: ?, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: 1, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)     koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 14, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 /\ Ar_0 - 6 >= 101 /\ 100 >= Ar_0 - 16 /\ Ar_0 - 5 >= 101 /\ 100 >= Ar_0 - 15 /\ Ar_0 - 4 >= 101 ] with all transitions in problem 20, the following new transition is obtained:
	f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 3, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 /\ Ar_0 - 6 >= 101 /\ 100 >= Ar_0 - 16 /\ Ar_0 - 5 >= 101 /\ 100 >= Ar_0 - 15 /\ Ar_0 - 4 >= 101 /\ 100 >= Ar_0 - 14 ]
We thus obtain the following problem:
21:	T:
		(Comp: 1, Cost: 15)    f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 3, Ar_1 - 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ Ar_0 - 9 >= 101 /\ Ar_1 - 2 >= 1 /\ 100 >= Ar_0 - 19 /\ Ar_0 - 8 >= 101 /\ 100 >= Ar_0 - 18 /\ Ar_0 - 7 >= 101 /\ 100 >= Ar_0 - 17 /\ Ar_0 - 6 >= 101 /\ 100 >= Ar_0 - 16 /\ Ar_0 - 5 >= 101 /\ 100 >= Ar_0 - 15 /\ Ar_0 - 4 >= 101 /\ 100 >= Ar_0 - 14 ]
		(Comp: 1, Cost: 4)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 2, Ar_1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ 100 >= Ar_0 - 10 /\ Ar_0 + 1 >= 101 /\ 100 >= Ar_0 - 9 ]
		(Comp: 1, Cost: 2)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 20, Ar_1 - 2, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ Ar_0 >= 101 /\ 0 >= Ar_2 /\ Ar_1 >= 1 /\ 1 >= 0 /\ Ar_1 - 1 >= 1 /\ Ar_0 - 10 >= 101 ]
		(Comp: 1, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f2(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_3 >= Ar_0 /\ Ar_2 >= 1 /\ Ar_1 >= Ar_4 ]
		(Comp: ?, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 - 10, Ar_1 - 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ Ar_0 >= 101 ]
		(Comp: ?, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, Ar_2, Ar_3, Ar_4)) [ Ar_2 >= 0 /\ Ar_1 >= 1 /\ 100 >= Ar_0 ]
		(Comp: 1, Cost: 1)     f1(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Ar_0 + 11, Ar_1 + 1, 1, Ar_0, Ar_1)) [ Ar_2 >= 0 /\ 100 >= Ar_0 /\ 0 >= Ar_2 /\ Ar_1 >= 1 ]
		(Comp: 1, Cost: 1)     koat_start(Ar_0, Ar_1, Ar_2, Ar_3, Ar_4) -> Com_1(f1(Fresh_0, 1, 0, Ar_3, Ar_4)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

Complexity upper bound ?

Time: 0.683 sec (SMT: 0.546 sec)
