
Initial complexity problem:
1:	T:
		(Comp: ?, Cost: 1)    f0(Ar_0, Ar_1, Ar_2) -> Com_1(f15(2, Ar_1, Ar_2))
		(Comp: ?, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ 10 >= Ar_0 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ D >= E + 1 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2))
		(Comp: ?, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 >= 11 ]
		(Comp: 1, Cost: 0)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f0(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

Repeatedly propagating knowledge in problem 1 produces the following problem:
2:	T:
		(Comp: 1, Cost: 1)    f0(Ar_0, Ar_1, Ar_2) -> Com_1(f15(2, Ar_1, Ar_2))
		(Comp: ?, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ 10 >= Ar_0 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ D >= E + 1 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2))
		(Comp: ?, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 >= 11 ]
		(Comp: 1, Cost: 0)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f0(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

A polynomial rank function with
	Pol(f0) = 1
	Pol(f15) = 1
	Pol(f18) = 1
	Pol(f28) = 0
	Pol(koat_start) = 1
orients all transitions weakly and the transition
	f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 >= 11 ]
strictly and produces the following problem:
3:	T:
		(Comp: 1, Cost: 1)    f0(Ar_0, Ar_1, Ar_2) -> Com_1(f15(2, Ar_1, Ar_2))
		(Comp: ?, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ 10 >= Ar_0 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ D >= E + 1 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2))
		(Comp: 1, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 >= 11 ]
		(Comp: 1, Cost: 0)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f0(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

A polynomial rank function with
	Pol(f0) = 9
	Pol(f15) = -V_1 + 11
	Pol(f18) = -V_1 + 10
	Pol(f28) = -V_1
	Pol(koat_start) = 9
orients all transitions weakly and the transition
	f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ 10 >= Ar_0 ]
strictly and produces the following problem:
4:	T:
		(Comp: 1, Cost: 1)    f0(Ar_0, Ar_1, Ar_2) -> Com_1(f15(2, Ar_1, Ar_2))
		(Comp: 9, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ 10 >= Ar_0 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ D >= E + 1 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2))
		(Comp: 1, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 >= 11 ]
		(Comp: 1, Cost: 0)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f0(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

A polynomial rank function with
	Pol(f18) = 1
	Pol(f15) = 0
and size complexities
	S("koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f0(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ]", 0-0) = Ar_0
	S("koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f0(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ]", 0-1) = Ar_1
	S("koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f0(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ]", 0-2) = Ar_2
	S("f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 >= 11 ]", 0-0) = ?
	S("f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 >= 11 ]", 0-1) = ?
	S("f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 >= 11 ]", 0-2) = ?
	S("f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2))", 0-0) = ?
	S("f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2))", 0-1) = ?
	S("f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2))", 0-2) = ?
	S("f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ D >= E + 1 ]", 0-0) = ?
	S("f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ D >= E + 1 ]", 0-1) = ?
	S("f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ D >= E + 1 ]", 0-2) = ?
	S("f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ 10 >= Ar_0 ]", 0-0) = ?
	S("f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ 10 >= Ar_0 ]", 0-1) = ?
	S("f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ 10 >= Ar_0 ]", 0-2) = ?
	S("f0(Ar_0, Ar_1, Ar_2) -> Com_1(f15(2, Ar_1, Ar_2))", 0-0) = 2
	S("f0(Ar_0, Ar_1, Ar_2) -> Com_1(f15(2, Ar_1, Ar_2))", 0-1) = Ar_1
	S("f0(Ar_0, Ar_1, Ar_2) -> Com_1(f15(2, Ar_1, Ar_2))", 0-2) = Ar_2
orients the transitions
	f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ D >= E + 1 ]
	f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2))
weakly and the transition
	f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2))
strictly and produces the following problem:
5:	T:
		(Comp: 1, Cost: 1)    f0(Ar_0, Ar_1, Ar_2) -> Com_1(f15(2, Ar_1, Ar_2))
		(Comp: 9, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ 10 >= Ar_0 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ D >= E + 1 ]
		(Comp: 9, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2))
		(Comp: 1, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 >= 11 ]
		(Comp: 1, Cost: 0)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f0(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

Applied AI with 'oct' on problem 5 to obtain the following invariants:
  For symbol f15: X_1 - 2 >= 0
  For symbol f18: -X_2 + 10 >= 0 /\ X_1 - X_2 >= 0 /\ -X_1 - X_2 + 20 >= 0 /\ -X_1 + 10 >= 0 /\ X_1 - 2 >= 0


This yielded the following problem:
6:	T:
		(Comp: 1, Cost: 0)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f0(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ]
		(Comp: 1, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 - 2 >= 0 /\ Ar_0 >= 11 ]
		(Comp: 9, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 /\ D >= E + 1 ]
		(Comp: 9, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ Ar_0 - 2 >= 0 /\ 10 >= Ar_0 ]
		(Comp: 1, Cost: 1)    f0(Ar_0, Ar_1, Ar_2) -> Com_1(f15(2, Ar_1, Ar_2))
	start location:	koat_start
	leaf cost:	0

By chaining the transition koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f0(Ar_0, Ar_1, Ar_2)) [ 0 <= 0 ] with all transitions in problem 6, the following new transition is obtained:
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(2, Ar_1, Ar_2)) [ 0 <= 0 ]
We thus obtain the following problem:
7:	T:
		(Comp: 1, Cost: 1)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(2, Ar_1, Ar_2)) [ 0 <= 0 ]
		(Comp: 1, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 - 2 >= 0 /\ Ar_0 >= 11 ]
		(Comp: 9, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 /\ D >= E + 1 ]
		(Comp: 9, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ Ar_0 - 2 >= 0 /\ 10 >= Ar_0 ]
		(Comp: 1, Cost: 1)    f0(Ar_0, Ar_1, Ar_2) -> Com_1(f15(2, Ar_1, Ar_2))
	start location:	koat_start
	leaf cost:	0

Testing for reachability in the complexity graph removes the following transition from problem 7:
	f0(Ar_0, Ar_1, Ar_2) -> Com_1(f15(2, Ar_1, Ar_2))
We thus obtain the following problem:
8:	T:
		(Comp: 1, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 - 2 >= 0 /\ Ar_0 >= 11 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 /\ D >= E + 1 ]
		(Comp: 9, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 ]
		(Comp: 9, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ Ar_0 - 2 >= 0 /\ 10 >= Ar_0 ]
		(Comp: 1, Cost: 1)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(2, Ar_1, Ar_2)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(2, Ar_1, Ar_2)) [ 0 <= 0 ] with all transitions in problem 8, the following new transition is obtained:
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(2, 2, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 ]
We thus obtain the following problem:
9:	T:
		(Comp: 1, Cost: 2)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(2, 2, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 ]
		(Comp: 1, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 - 2 >= 0 /\ Ar_0 >= 11 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 /\ D >= E + 1 ]
		(Comp: 9, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 ]
		(Comp: 9, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ Ar_0 - 2 >= 0 /\ 10 >= Ar_0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(2, 2, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 ] with all transitions in problem 9, the following new transitions are obtained:
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(2, 1, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ D >= E + 1 ]
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(3, 2, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 ]
We thus obtain the following problem:
10:	T:
		(Comp: 1, Cost: 3)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(2, 1, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 3)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(3, 2, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 ]
		(Comp: 1, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 - 2 >= 0 /\ Ar_0 >= 11 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 /\ D >= E + 1 ]
		(Comp: 9, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 ]
		(Comp: 9, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ Ar_0 - 2 >= 0 /\ 10 >= Ar_0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(3, 2, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 ] with all transitions in problem 10, the following new transition is obtained:
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(3, 3, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 ]
We thus obtain the following problem:
11:	T:
		(Comp: 1, Cost: 4)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(3, 3, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 ]
		(Comp: 1, Cost: 3)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(2, 1, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 - 2 >= 0 /\ Ar_0 >= 11 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 /\ D >= E + 1 ]
		(Comp: 9, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 ]
		(Comp: 9, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ Ar_0 - 2 >= 0 /\ 10 >= Ar_0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(3, 3, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 ] with all transitions in problem 11, the following new transitions are obtained:
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(3, 2, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ D >= E + 1 ]
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(4, 3, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 ]
We thus obtain the following problem:
12:	T:
		(Comp: 1, Cost: 5)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(3, 2, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 5)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(4, 3, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 ]
		(Comp: 1, Cost: 3)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(2, 1, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 - 2 >= 0 /\ Ar_0 >= 11 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 /\ D >= E + 1 ]
		(Comp: 9, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 ]
		(Comp: 9, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ Ar_0 - 2 >= 0 /\ 10 >= Ar_0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(4, 3, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 ] with all transitions in problem 12, the following new transition is obtained:
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(4, 4, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 ]
We thus obtain the following problem:
13:	T:
		(Comp: 1, Cost: 6)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(4, 4, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 ]
		(Comp: 1, Cost: 5)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(3, 2, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 3)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(2, 1, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 - 2 >= 0 /\ Ar_0 >= 11 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 /\ D >= E + 1 ]
		(Comp: 9, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 ]
		(Comp: 9, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ Ar_0 - 2 >= 0 /\ 10 >= Ar_0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(4, 4, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 ] with all transitions in problem 13, the following new transitions are obtained:
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(4, 3, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ D >= E + 1 ]
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(5, 4, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 ]
We thus obtain the following problem:
14:	T:
		(Comp: 1, Cost: 7)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(4, 3, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 7)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(5, 4, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 ]
		(Comp: 1, Cost: 5)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(3, 2, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 3)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(2, 1, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 - 2 >= 0 /\ Ar_0 >= 11 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 /\ D >= E + 1 ]
		(Comp: 9, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 ]
		(Comp: 9, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ Ar_0 - 2 >= 0 /\ 10 >= Ar_0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(5, 4, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 ] with all transitions in problem 14, the following new transition is obtained:
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(5, 5, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 ]
We thus obtain the following problem:
15:	T:
		(Comp: 1, Cost: 8)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(5, 5, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 ]
		(Comp: 1, Cost: 7)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(4, 3, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 5)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(3, 2, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 3)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(2, 1, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 - 2 >= 0 /\ Ar_0 >= 11 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 /\ D >= E + 1 ]
		(Comp: 9, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 ]
		(Comp: 9, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ Ar_0 - 2 >= 0 /\ 10 >= Ar_0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(5, 5, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 ] with all transitions in problem 15, the following new transitions are obtained:
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(5, 4, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ D >= E + 1 ]
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(6, 5, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 ]
We thus obtain the following problem:
16:	T:
		(Comp: 1, Cost: 9)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(5, 4, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 9)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(6, 5, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 ]
		(Comp: 1, Cost: 7)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(4, 3, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 5)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(3, 2, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 3)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(2, 1, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 - 2 >= 0 /\ Ar_0 >= 11 ]
		(Comp: ?, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 /\ D >= E + 1 ]
		(Comp: 9, Cost: 1)    f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 ]
		(Comp: 9, Cost: 1)    f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ Ar_0 - 2 >= 0 /\ 10 >= Ar_0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(6, 5, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 ] with all transitions in problem 16, the following new transition is obtained:
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(6, 6, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 ]
We thus obtain the following problem:
17:	T:
		(Comp: 1, Cost: 10)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(6, 6, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 ]
		(Comp: 1, Cost: 9)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(5, 4, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 7)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(4, 3, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 5)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(3, 2, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 3)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(2, 1, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 1)     f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 - 2 >= 0 /\ Ar_0 >= 11 ]
		(Comp: ?, Cost: 1)     f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 /\ D >= E + 1 ]
		(Comp: 9, Cost: 1)     f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 ]
		(Comp: 9, Cost: 1)     f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ Ar_0 - 2 >= 0 /\ 10 >= Ar_0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(6, 6, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 ] with all transitions in problem 17, the following new transitions are obtained:
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(6, 5, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ D >= E + 1 ]
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(7, 6, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 ]
We thus obtain the following problem:
18:	T:
		(Comp: 1, Cost: 11)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(6, 5, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ D >= E + 1 ]
		(Comp: 1, Cost: 11)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(7, 6, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 ]
		(Comp: 1, Cost: 9)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(5, 4, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 7)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(4, 3, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 5)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(3, 2, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 3)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(2, 1, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 1)     f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 - 2 >= 0 /\ Ar_0 >= 11 ]
		(Comp: ?, Cost: 1)     f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 /\ D >= E + 1 ]
		(Comp: 9, Cost: 1)     f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 ]
		(Comp: 9, Cost: 1)     f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ Ar_0 - 2 >= 0 /\ 10 >= Ar_0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(7, 6, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 ] with all transitions in problem 18, the following new transition is obtained:
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(7, 7, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ 10 >= 7 ]
We thus obtain the following problem:
19:	T:
		(Comp: 1, Cost: 12)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(7, 7, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ 10 >= 7 ]
		(Comp: 1, Cost: 11)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(6, 5, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ D >= E + 1 ]
		(Comp: 1, Cost: 9)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(5, 4, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 7)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(4, 3, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 5)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(3, 2, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 3)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(2, 1, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 1)     f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 - 2 >= 0 /\ Ar_0 >= 11 ]
		(Comp: ?, Cost: 1)     f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 /\ D >= E + 1 ]
		(Comp: 9, Cost: 1)     f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 ]
		(Comp: 9, Cost: 1)     f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ Ar_0 - 2 >= 0 /\ 10 >= Ar_0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(7, 7, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ 10 >= 7 ] with all transitions in problem 19, the following new transitions are obtained:
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(7, 6, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ 10 >= 7 /\ D >= E + 1 ]
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(8, 7, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ 10 >= 7 ]
We thus obtain the following problem:
20:	T:
		(Comp: 1, Cost: 13)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(7, 6, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ 10 >= 7 /\ D >= E + 1 ]
		(Comp: 1, Cost: 13)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(8, 7, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ 10 >= 7 ]
		(Comp: 1, Cost: 11)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(6, 5, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ D >= E + 1 ]
		(Comp: 1, Cost: 9)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(5, 4, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 7)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(4, 3, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 5)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(3, 2, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 3)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(2, 1, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 1)     f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 - 2 >= 0 /\ Ar_0 >= 11 ]
		(Comp: ?, Cost: 1)     f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 /\ D >= E + 1 ]
		(Comp: 9, Cost: 1)     f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 ]
		(Comp: 9, Cost: 1)     f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ Ar_0 - 2 >= 0 /\ 10 >= Ar_0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(8, 7, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ 10 >= 7 ] with all transitions in problem 20, the following new transition is obtained:
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(8, 8, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 ]
We thus obtain the following problem:
21:	T:
		(Comp: 1, Cost: 14)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(8, 8, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 ]
		(Comp: 1, Cost: 13)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(7, 6, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ 10 >= 7 /\ D >= E + 1 ]
		(Comp: 1, Cost: 11)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(6, 5, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ D >= E + 1 ]
		(Comp: 1, Cost: 9)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(5, 4, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 7)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(4, 3, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 5)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(3, 2, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 3)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(2, 1, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 1)     f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 - 2 >= 0 /\ Ar_0 >= 11 ]
		(Comp: ?, Cost: 1)     f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 /\ D >= E + 1 ]
		(Comp: 9, Cost: 1)     f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 ]
		(Comp: 9, Cost: 1)     f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ Ar_0 - 2 >= 0 /\ 10 >= Ar_0 ]
	start location:	koat_start
	leaf cost:	0

By chaining the transition koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(8, 8, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 ] with all transitions in problem 21, the following new transitions are obtained:
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(8, 7, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ D >= E + 1 ]
	koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(9, 8, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 ]
We thus obtain the following problem:
22:	T:
		(Comp: 1, Cost: 15)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(8, 7, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 /\ D >= E + 1 ]
		(Comp: 1, Cost: 15)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f15(9, 8, Ar_2)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ 10 >= 7 /\ 10 >= 8 ]
		(Comp: 1, Cost: 13)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(7, 6, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ 10 >= 7 /\ D >= E + 1 ]
		(Comp: 1, Cost: 11)    koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(6, 5, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ 4 >= 0 /\ 10 >= 6 /\ D >= E + 1 ]
		(Comp: 1, Cost: 9)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(5, 4, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ 3 >= 0 /\ 10 >= 5 /\ 5 >= 0 /\ 10 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 7)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(4, 3, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ 2 >= 0 /\ 10 >= 4 /\ 6 >= 0 /\ 12 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 5)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(3, 2, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ 1 >= 0 /\ 10 >= 3 /\ 7 >= 0 /\ 14 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 3)     koat_start(Ar_0, Ar_1, Ar_2) -> Com_1(f18(2, 1, Fresh_0)) [ 0 <= 0 /\ 0 >= 0 /\ 10 >= 2 /\ 8 >= 0 /\ 16 >= 0 /\ D >= E + 1 ]
		(Comp: 1, Cost: 1)     f15(Ar_0, Ar_1, Ar_2) -> Com_1(f28(Ar_0, Ar_1, Ar_2)) [ Ar_0 - 2 >= 0 /\ Ar_0 >= 11 ]
		(Comp: ?, Cost: 1)     f18(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_1 - 1, Fresh_0)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 /\ D >= E + 1 ]
		(Comp: 9, Cost: 1)     f18(Ar_0, Ar_1, Ar_2) -> Com_1(f15(Ar_0 + 1, Ar_1, Ar_2)) [ -Ar_1 + 10 >= 0 /\ Ar_0 - Ar_1 >= 0 /\ -Ar_0 - Ar_1 + 20 >= 0 /\ -Ar_0 + 10 >= 0 /\ Ar_0 - 2 >= 0 ]
		(Comp: 9, Cost: 1)     f15(Ar_0, Ar_1, Ar_2) -> Com_1(f18(Ar_0, Ar_0, Ar_2)) [ Ar_0 - 2 >= 0 /\ 10 >= Ar_0 ]
	start location:	koat_start
	leaf cost:	0

Complexity upper bound ?

Time: 0.231 sec (SMT: 0.178 sec)
