
Initial complexity problem:
1:	T:
		(Comp: ?, Cost: 1)    f1(Ar_0, Ar_1) -> Com_1(f2(Ar_0, Ar_1)) [ Ar_0 >= 1 /\ Ar_1 >= 1 ]
		(Comp: ?, Cost: 1)    f2(Ar_0, Ar_1) -> Com_1(f2(Ar_0 - 1, Ar_1)) [ Ar_0 >= 2 /\ Ar_1 >= 1 ]
		(Comp: ?, Cost: 1)    f2(Ar_0, Ar_1) -> Com_1(f2(Ar_0, Ar_1 - 1)) [ Ar_0 >= 1 /\ Ar_1 >= 2 ]
		(Comp: 1, Cost: 0)    koat_start(Ar_0, Ar_1) -> Com_1(f1(Ar_0, Ar_1)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

Repeatedly propagating knowledge in problem 1 produces the following problem:
2:	T:
		(Comp: 1, Cost: 1)    f1(Ar_0, Ar_1) -> Com_1(f2(Ar_0, Ar_1)) [ Ar_0 >= 1 /\ Ar_1 >= 1 ]
		(Comp: ?, Cost: 1)    f2(Ar_0, Ar_1) -> Com_1(f2(Ar_0 - 1, Ar_1)) [ Ar_0 >= 2 /\ Ar_1 >= 1 ]
		(Comp: ?, Cost: 1)    f2(Ar_0, Ar_1) -> Com_1(f2(Ar_0, Ar_1 - 1)) [ Ar_0 >= 1 /\ Ar_1 >= 2 ]
		(Comp: 1, Cost: 0)    koat_start(Ar_0, Ar_1) -> Com_1(f1(Ar_0, Ar_1)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

A polynomial rank function with
	Pol(f1) = V_1 + V_2
	Pol(f2) = V_1 + V_2
	Pol(koat_start) = V_1 + V_2
orients all transitions weakly and the transitions
	f2(Ar_0, Ar_1) -> Com_1(f2(Ar_0, Ar_1 - 1)) [ Ar_0 >= 1 /\ Ar_1 >= 2 ]
	f2(Ar_0, Ar_1) -> Com_1(f2(Ar_0 - 1, Ar_1)) [ Ar_0 >= 2 /\ Ar_1 >= 1 ]
strictly and produces the following problem:
3:	T:
		(Comp: 1, Cost: 1)              f1(Ar_0, Ar_1) -> Com_1(f2(Ar_0, Ar_1)) [ Ar_0 >= 1 /\ Ar_1 >= 1 ]
		(Comp: Ar_0 + Ar_1, Cost: 1)    f2(Ar_0, Ar_1) -> Com_1(f2(Ar_0 - 1, Ar_1)) [ Ar_0 >= 2 /\ Ar_1 >= 1 ]
		(Comp: Ar_0 + Ar_1, Cost: 1)    f2(Ar_0, Ar_1) -> Com_1(f2(Ar_0, Ar_1 - 1)) [ Ar_0 >= 1 /\ Ar_1 >= 2 ]
		(Comp: 1, Cost: 0)              koat_start(Ar_0, Ar_1) -> Com_1(f1(Ar_0, Ar_1)) [ 0 <= 0 ]
	start location:	koat_start
	leaf cost:	0

Complexity upper bound 2*Ar_0 + 2*Ar_1 + 1

Time: 0.022 sec (SMT: 0.020 sec)
